111 IOLI 0x02
This is the third one.
$ ./crackme0x02
IOLI Crackme Level 0x02
Password: hello
Invalid Password!
Firstly, let’s check it with rz-bin.
$ rz-bin -z ./crackme0x02
[Strings]
nth paddr vaddr len size section type string
―――――――――――――――――――――――――――――――――――――――――――――――――――――――
0 0x00000548 0x08048548 24 25 .rodata ascii IOLI Crackme Level 0x02\n
1 0x00000561 0x08048561 10 11 .rodata ascii Password:
2 0x0000056f 0x0804856f 15 16 .rodata ascii Password OK :)\n
3 0x0000057f 0x0804857f 18 19 .rodata ascii Invalid Password!\n
Similar to 0x01, there’s no explicit password string here. So, it’s time to analyze it with Rizin.
[0x08048330]> aa
[x] Analyze all flags starting with sym. and entry0 (aa)
[0x08048330]> pdf@main
; DATA XREF from entry0 @ 0x8048347
/ 144: int main (int argc, char **argv, char **envp);
| ; var int32_t var_ch @ ebp-0xc
| ; var int32_t var_8h @ ebp-0x8
| ; var int32_t var_4h @ ebp-0x4
| ; var int32_t var_sp_4h @ esp+0x4
| 0x080483e4 55 push ebp
| 0x080483e5 89e5 mov ebp, esp
| 0x080483e7 83ec18 sub esp, 0x18
| 0x080483ea 83e4f0 and esp, 0xfffffff0
| 0x080483ed b800000000 mov eax, 0
| 0x080483f2 83c00f add eax, 0xf ; 15
| 0x080483f5 83c00f add eax, 0xf ; 15
| 0x080483f8 c1e804 shr eax, 4
| 0x080483fb c1e004 shl eax, 4
| 0x080483fe 29c4 sub esp, eax
| 0x08048400 c70424488504. mov dword [esp], str.IOLI_Crackme_Level_0x02 ; [0x8048548:4]=0x494c4f49 ; "IOLI Crackme Level 0x02\n"
| 0x08048407 e810ffffff call sym.imp.printf ; int printf(const char *format)
| 0x0804840c c70424618504. mov dword [esp], str.Password: ; [0x8048561:4]=0x73736150 ; "Password: "
| 0x08048413 e804ffffff call sym.imp.printf ; int printf(const char *format)
| 0x08048418 8d45fc lea eax, [var_4h]
| 0x0804841b 89442404 mov dword [var_sp_4h], eax
| 0x0804841f c704246c8504. mov dword [esp], 0x804856c ; [0x804856c:4]=0x50006425
| 0x08048426 e8e1feffff call sym.imp.scanf ; int scanf(const char *format)
| 0x0804842b c745f85a0000. mov dword [var_8h], 0x5a ; 'Z' ; 90
| 0x08048432 c745f4ec0100. mov dword [var_ch], 0x1ec ; 492
| 0x08048439 8b55f4 mov edx, dword [var_ch]
| 0x0804843c 8d45f8 lea eax, [var_8h]
| 0x0804843f 0110 add dword [eax], edx
| 0x08048441 8b45f8 mov eax, dword [var_8h]
| 0x08048444 0faf45f8 imul eax, dword [var_8h]
| 0x08048448 8945f4 mov dword [var_ch], eax
| 0x0804844b 8b45fc mov eax, dword [var_4h]
| 0x0804844e 3b45f4 cmp eax, dword [var_ch]
| ,=< 0x08048451 750e jne 0x8048461
| | 0x08048453 c704246f8504. mov dword [esp], str.Password_OK_: ; [0x804856f:4]=0x73736150 ; "Password OK :)\n"
| | 0x0804845a e8bdfeffff call sym.imp.printf ; int printf(const char *format)
| ,==< 0x0804845f eb0c jmp 0x804846d
| |`-> 0x08048461 c704247f8504. mov dword [esp], str.Invalid_Password ; [0x804857f:4]=0x61766e49 ; "Invalid Password!\n"
| | 0x08048468 e8affeffff call sym.imp.printf ; int printf(const char *format)
| | ; CODE XREF from main @ 0x804845f
| `--> 0x0804846d b800000000 mov eax, 0
| 0x08048472 c9 leave
\ 0x08048473 c3 ret
With the experience of solving crackme0x01, we can first locate the position of cmp
instruction by using this simple oneliner:
[0x08048330]> pdf@main~cmp
| 0x0804844e 3b45f4 cmp eax, dword [var_ch]
Unfortunately, the variable compared to eax
is stored in the stack. We can’t check the value of this variable directly. It’s a common case in reverse engineering that we have to derive the value of the variable from the previous sequence. As the amount of code is relatively small, it can be easily done.
for example:
| 0x080483ed b800000000 mov eax, 0
| 0x080483f2 83c00f add eax, 0xf ; 15
| 0x080483f5 83c00f add eax, 0xf ; 15
| 0x080483f8 c1e804 shr eax, 4
| 0x080483fb c1e004 shl eax, 4
| 0x080483fe 29c4 sub esp, eax
We can easily get the value of eax
. It’s 16.
Directly looking at the disassembly gets hard when the scale of program grows. Rizin’s flagship decompiler rz-ghidra might be of help, here. You can install it easily:
rz-pm -i rz-ghidra
Decompile main()
with the following command (like F5
in IDA):
[0x08048330]> pdg
(void)
undefined4 main{
uint32_t var_ch;
;
undefined4 var_8hint32_t var_4h;
("IOLI Crackme Level 0x02\n");
printf("Password: ");
printf(0x804856c, &var_4h);
scanfif (var_4h == 0x52b24) {
("Password OK :)\n");
printf} else {
("Invalid Password!\n");
printf}
return 0;
}
It’s more human-readable now. To check the string in 0x804856c
, we can: * Seek * Print the string
[0x08048330]> s 0x804856c
[0x0804856c]> ps
%d
It’s exactly the format string of scanf()
. And rz-ghidra recognizes that the second argument (eax) is a pointer and it points to var_4h
. Which means our input will be stored in var_4h
.
We can easily write out the pseudo code here.
= (var_8h + var_ch)^2;
var_ch if (var_ch == our_input)
("Password OK :)\n"); printf
Given the initial status that var_8h
is 0x5a
, var_ch
is 0x1ec
, we have var_ch = 338724 (0x52b24):
$ rz-ax '=10' '(0x5a+0x1ec)*(0x5a+0x1ec)'
338724
$ ./crackme0x02
IOLI Crackme Level 0x02
Password: 338724
Password OK :)
And we finish the crackme0x02.